find two consecutive numbers such that the greater number added to 3 times of the smaller number makes a total of 53
Answers
Answered by
15
Two consecutive numbers are pairs of numbers like
1,2
or
18,19
one right after the other". That is, one of the integers is immediately to the right of the other, when viewed on a number line.
Denote the smaller integer using
Then the larger of the two consecutiveintegers must be
n+1
n+1
. That leaves us with solving the following:
n+(n+1)=2n+1=53.
n+(n+1)=2n+1=53.
That means
2n=53−1=52,
2n=53−1=52,
so
n=
52
2
=26
n=522=26
So, we have
n=26,n+1=27,
n=26,n+1=27,
as desired.
answered
Aug 10 '14 at 14:34
1
x+(x+1)=532x+1=53
2x=52x=26
x+(x+1)=532x+1=532x=52x=26
The numbers are:
x=26
x=26
and
x+1=27
x+1=27
1,2
or
18,19
one right after the other". That is, one of the integers is immediately to the right of the other, when viewed on a number line.
Denote the smaller integer using
Then the larger of the two consecutiveintegers must be
n+1
n+1
. That leaves us with solving the following:
n+(n+1)=2n+1=53.
n+(n+1)=2n+1=53.
That means
2n=53−1=52,
2n=53−1=52,
so
n=
52
2
=26
n=522=26
So, we have
n=26,n+1=27,
n=26,n+1=27,
as desired.
answered
Aug 10 '14 at 14:34
1
x+(x+1)=532x+1=53
2x=52x=26
x+(x+1)=532x+1=532x=52x=26
The numbers are:
x=26
x=26
and
x+1=27
x+1=27
Nakulgoel:
Hlo
Answered by
12
if we mulitiply 13 with 3 product is 39 and if we add 14 in 39 the answer is 53
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