find two consecutive numbers where thrice the first number is more than twice the second number by 5
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Answered by
8
Answer:
Step-by-step explanation:
Let the two consecutive numbers be x and (x + 1) respectively.
According to the question ;
Thrice the first number is more than twice the second number by 5.
3x = 2(x + 1) + 5
⇒ 3x = 2x + 2 + 5
⇒ 3x = 2x + 7
⇒ 3x - 2x = 7
⇒ x = 7
Thus, the numbers are;
- x = 7
- x + 1 = 7 + 1 = 8
Hence, the numbers are 7 and 8.
Answered by
2
Answer:
Let the consecutive numbers be X and X+1
According to the question :
3(x) = 2(x+1) + 5
3x =2x + 2 + 5
3x-2x=7
Therefore, x =7
Hence two no.s are 7 and 8
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