Question

find two consecutive numbers where thrice the first number is more than twice the second number by 5​

Answer 1

Answer:

$\large{\underline{\boxed{\sf 7 \: \: and \: \: 8}}}$

Step-by-step explanation:

Let the two consecutive numbers be x and (x + 1) respectively.

According to the question ;

Thrice the first number is more than twice the second number by 5.

3x = 2(x + 1) + 5

⇒ 3x = 2x + 2 + 5

⇒ 3x = 2x + 7

⇒ 3x - 2x = 7

⇒ x = 7

Thus, the numbers are;

• x = 7
• x + 1 = 7 + 1 = 8

Hence, the numbers are 7 and 8.

Answer 2

Answer:

Let the consecutive numbers be X and X+1

According to the question :

3(x) = 2(x+1) + 5

3x =2x + 2 + 5

3x-2x=7

Therefore, x =7

Hence two no.s are 7 and 8