Find two consecutive numbers where thrice the first number is more than twice the second number by 5
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Answered by
21
hey !!
Let the two consecutive numbers be 'x' and 'x+1'
According to the question,
3x=2(x+1)+5
-->3x=2x+2+5
-->3x-2x=2+5
-->x=7
Hence, the numbers are x=7 and (x+1)=8 ANS.
Let the two consecutive numbers be 'x' and 'x+1'
According to the question,
3x=2(x+1)+5
-->3x=2x+2+5
-->3x-2x=2+5
-->x=7
Hence, the numbers are x=7 and (x+1)=8 ANS.
Adarsh9450668057:
first no =7
Answered by
6
Answer:
Numbers are 7 & 8
Step-by-step explanation:
Find two consecutive numbers where thrice the first number is more than twice the second number by 5
Let say Two number are X & X + 1
Thrice of First number = 3X
Twice of the seond number = 2(X + 1) = 2X + 2
thrice the first number is more than twice the second number by 5
3X = 2X + 2 + 5
=> X = 7
X + 1 = 8
Numbers are 7 & 8
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