Math, asked by shubhamrock9917, 1 year ago

Find two consecutive numbers where thrice the first number is more than twice the second number by 5

Answers

Answered by Anonymous
21
hey !!
Let the two consecutive numbers be 'x' and 'x+1'
According to the question,
3x=2(x+1)+5
-->3x=2x+2+5
-->3x-2x=2+5
-->x=7
Hence, the numbers are x=7 and (x+1)=8 ANS.

Adarsh9450668057: first no =7
Adarsh9450668057: first no.=7 and second no.=8 ATQ, 3*7=2*8+5 ,21=16+5 ,21=21, hence verified...
Answered by amitnrw
6

Answer:

Numbers are  7 & 8

Step-by-step explanation:

Find two consecutive numbers where thrice the first number is more than twice the second number by 5

Let say Two number are  X  & X + 1

Thrice of First number = 3X

Twice of the seond number = 2(X + 1) = 2X + 2

thrice the first number is more than twice the second number by 5

3X = 2X + 2 + 5

=> X = 7

X + 1 = 8

Numbers are  7 & 8

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