find two consecutive numbers whose square have the sum 85
Answers
Answered by
1
Hi Friend !!!
Here is ur answer !!!
Let the number be x and x+1
x+1+x = 85
2x =85-1
x = 84/2
x = 42
So the numbers are 42,43
Here is ur answer !!!
Let the number be x and x+1
x+1+x = 85
2x =85-1
x = 84/2
x = 42
So the numbers are 42,43
vaibhav358:
wrong
Answered by
2
Hey!!!
____________
Here is your answer!!@
_____________
Let one number =x
Other number =x+1
According to the question
x^2+(x+1)^2=85
x^2+x^2+1+2x=85
2x^2+1+2x=85
2x^2+2x-84=0
x^2+x-42=0
x^2+(7-6)x-42=0
x^2+7x-6x-42=0
x(x+7)-6(x+7)=0
(x+7)(x-6)=0
Number =-7 or 6
Other number =-6 or 7
____________
I hope it will help you!!!
____________
Here is your answer!!@
_____________
Let one number =x
Other number =x+1
According to the question
x^2+(x+1)^2=85
x^2+x^2+1+2x=85
2x^2+1+2x=85
2x^2+2x-84=0
x^2+x-42=0
x^2+(7-6)x-42=0
x^2+7x-6x-42=0
x(x+7)-6(x+7)=0
(x+7)(x-6)=0
Number =-7 or 6
Other number =-6 or 7
____________
I hope it will help you!!!
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