Question

find two consecutive numbers with a product of 182

Answer 1

One way to find out is write a formula. Let N and N+1 be the two integers, then. N(N+1) = 182. N^2 + N - 182 = 0. This is a quadratic equation. If the factors are not obvious, (N -13)(N + 14) , then use the quadratic formula to find N.. The factors tell you there are two possible solutions for N; 13 and -14. Now add 1 to these to get the two consecutive integers. 13 & 14 will work and -14 & -13 will work.

Answer 2

Hey....Friend.

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Here is your answer. ...

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let the no.be x and x+1

Now According to question...

x(x+1)=182

${x}^{2} + x = 182 \\ {x}^{2} + x - 182 = 0 \\ {x}^{2} + 14x - 13x - 182 = 0 \\ x(x + 14) - 13(x + 14) = 0 \\ (x - 13)(x + 14) = 0$
x=13,-14
..

so x=13

x+1=13+1

14

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