Question

Find two consecutive odd integer,sum of whose square is 290

Answer 1

Answer:

Step-by-step explanation:

let x ,x +1 be a consecutive positive number

given square of them is 290

{x}^2 + {x+2}^2 = 290

x^2 + x^2 + 4x + 4  = 290

2x^2 +4x + 286 = 0  divide by 2

x^2 + 2x + 143 = 0

now use factorisation  method

so we get factors of 143 is 11 and 13

so x = 13 or -11