Question

Find two consecutive odd integers if the sum of their squares is 202​

Answer 1

Step-by-step explanation:

Find two consecutive odd integers if the sum of their squares is 202

Answer 2

Answer:

We have,

Let the two odd consecutive numbers xandx+2

So,

According to given question,

x

2

+(x+2)

2

=202

⇒x

2

+x

2

+4+4x=202

⇒2x

2

+4x=198

⇒x

2

+2x=99

⇒x

2

+2x−99=0

⇒x

2

+(11−9)x−99=0

⇒x

2

+11x−9x−99=0

⇒x(x+11)−9(x+11)=0

⇒(x+11)x−9=0

If,

x+11=0

⇒x=−11

If,

x−9=0

x=9

So,

x+2=9+2=11