Question

Find two consecutive odd integers such that 2/3 of the smaller integer exceeds 1/5 of larger one
by 15.​

Answer 1

Answer:

I can;t

long dxdcfv

Answer 2

Answer:

the smaller number is 33 and the larger is 35

Step-by-step explanation:

2/3x=1/5(x+2)+15

2/3x=1/5x+2/5+15

7/15x=2/5+15

7x=15(2/5+15)

7x=6+225

x=231/7

x=33

x+2=35