Question

Find two consecutive odd integers such that 2/5th of the smaller exceeds 2/9th of the greater by 4.Find the number??

Answer 1

Let the two consecutive odd integers be 2n-1 and 2n+1 for any value n.

Then

2*(2n-1)/5 - 2*(2n+1)/9 = 4

Multiplying both sides by 45, we get

18*(2n-1) - 10*(2n+1) = 4*45

36n-18-20n-10 = 180

16n-28 = 180

or 16n = 208.

Therefore n = 208/16 = 13.

Thus, the two numbers are 2*13-1 = 25 and 2*13+1 = 27.

Answer 2

I hope this will help you