Find two consecutive odd integers such that one third of the greater number exeeds two seventh of the lesser number by three.
Set up an equation in one variable and then solve the equation.
Answers
Answered by
1
26 votes
let the smaller no be xother no = x+2A/Qx/3=(x+2)/7 + 6x/3 - (x+2)/7 = 67x-3x-6/21=64x-6=1264x=132x= ... More
Similar questions