Find two consecutive odd integers such that one third of the greater number exeeds two seventh of the lesser number by three.
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Answer:
49 and 51
Step-by-step explanation:
Let smaller number be x and greater number be x+2.
Implies (x+2)/3 - 2x/7 = 3
7x+14 - 6x = 63 ... (making denominator 1)
Implies x + 14 = 63
x = 49 and x+2 = 49+2 = 51.
Hope this helps !
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