Question

find two consecutive odd integers such that the sum of their squares is 394 ​

Answer 1

Answer:

lthanks for you giving chance to solve a problem

Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Question}}}}$

Here,

Assume,

First consecutive odd numbers = p

Second number be (p + 2)

Now,

Situation,

p² + (p + 2)² = 394

2p² + 4p - 390 = 0

p² + 2p - 195 = 0

p² + 15p - 13p - 195 = 0

p(p + 15) - 13(p + 15) = 0

(p + 15) (p - 13) = 0

p + 15 = 0 or p - 13 = 0

p = -15, 13 (Negative value is not acceptable)

p = 13

First Number = p = 13

Second number

= p + 2

= 13 + 2

= 15