Find two consecutive odd integers such that the sum of their squares is 290
Answers
Answered by
3
Let the nos. be 2x+1 and 2x+3
(2x + 1)² + (2x+3)² = 290
4x² + 4x + 1 + 4x² + 12x + 9 = 290
8x² + 16x - 280 = 0
x² + 2x - 35 = 0
x = - 7 , 5
hence the nos . are
11 and 13
-11 and 13
Mark my answer as BRAINLIEST please!!!
aayushg1713:
sorry the second one is -11 and -13
Answered by
2
the numbers are -11 and-13 respectively
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