Question

Find two consecutive odd integers such that the sum of twice the lesser and three times greater is 191

Answer 1

Let x be the first number. X+2 is the second number. 2x + 3(x+2) = 191.

2x + 3x + 6 = 191

5x=185

X=37,

By putting value of X is 37

x = 37,

X+2=37+2=39

Hence X is 37 and X+2 is 39.

Answer 2

Answer:

• The required numbers are 37 and 39

Step-by-step explanation:

Let the numbers as x and x+2

here X < X+2

Now acc to the question.

2x + 3(X+2) = 191

2x +3x +6 = 191

5x = 191- 6

5x = 185

X = 185/5

x = 37

So

x +2 = 39

hope it may help you ♥