find two consecutive odd integers such that two-fifth of the smaller exceeds two-ninth of the greater by 4
Answers
Answered by
1
Let the smaller be x
2/5x+4=2/9x
2/9x -2/5x =4
10-18/45=4
2/5x+4=2/9x
2/9x -2/5x =4
10-18/45=4
Chirag241:
but the answer is 25,27
Similar questions