Question

find two consecutive odd integers such that two-fifth of the smaller exceeds two-ninth of the greater by 4

Answer 1

Let the first number be a

Second number = a+2

According to question

2a/5 - 2(a+2)/9 = 4

=> 18a - 10(a+2) /45 = 4

=> 18a - 10a - 20 = 180

=> 8a = 200

=> a = 25

First number = 25

Second number = 27