find two consecutive odd integers, sum of whose squore is 970
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Answered by
0
Answer:
let the two consecutive odd integers be X and X+1
Step-by-step explanation:
(X)^2 (X+1)^2 =970
solve this you will get the answers
Answered by
3
Let the two consecutive numbers be x and x+2 ( as they r consecutive odd)
Now
x^2+ (x+2)^2= 970
x^2+x^2+4+4x=970
2x^2+4x -966=0
2x^2+46x-42x-966=0
2x(x+23)-42(x+23)=0
(2x-42)(x+23)=0
x = 42/2 =21 and as x cannot be negative we neglect (x+23) case
Therefore two consecutive odd numbers = 21 , 23
Now
x^2+ (x+2)^2= 970
x^2+x^2+4+4x=970
2x^2+4x -966=0
2x^2+46x-42x-966=0
2x(x+23)-42(x+23)=0
(2x-42)(x+23)=0
x = 42/2 =21 and as x cannot be negative we neglect (x+23) case
Therefore two consecutive odd numbers = 21 , 23
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