Find two consecutive odd integers that the sum of sum of four time the larger and twice the smaller is 194
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Answer:let odd consecutive numbers be 2x+1,2x+3are smaller and larger numbers respectively,
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4*(larger no.)+2*(smaller no.) = 194
4*(2x+3) + 2*(2x+1) = 194
8x+12+4x+2 = 194
x = 15
therefore, Small no = 2x+1
=2*15+1=31
,Large number =2x+3
=2*15+3 = 33
The odd consecutive numbers are 31 and 33
Step-by-step explanation:
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