Question

find two consecutive odd natural no.the sum of whose square is202​

Answer 1

Answer:

using algebra...with x and x+2 the two consecutive odd integers

x2+(x+2)2=202

x2+x2+4x+4=202

2x2+4x+4-202=0

2x2+4x-198=0

divide both sides by 2

x2+2x-99=0

factor

(x+11)(x-9)=0

x-9=0

x=9

x+2=11

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