Question

Find two consecutive odd natural numbers, the sum of whose squares is 202.

Answer 1

talking about consecutive odd integer,

one will be (x),another( x+2)

x2 +(x+2)2=202

x2+x2+4+2x=202 (applying identity of [(a+b)2=a2 +2ab+b2])

2x2+2x-198=0

now further u can solve it easily by formula method.

Answer 2

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