Question

Find two consecutive odd number such that two fifths of the smaller exceeds two ninths of the greater by 4
​

Answer 1

Answer:

Ans.- 23 ⁶/8

Step-by-step explanation:

Let,

smaller no be x

greater no be x+1

2x = 2(x+1) + 4

5 9

2x = 2x + 2 + 4

5 9

2x = 2x + 2 + 36

5 9

18x = 5(2x + 38)

18x = 10x + 190

18x - 10x = 190

8x = 190

x = 190

8

x = 23 ⁶/8 or 23.75 ans.

hope it helps...

Keep asking, Keep Learning!

Mark as Brainliest!!!

Answer 2

Given :-

• Two consecutive odd number such that two fifths of the smaller exceeds two ninths of the greater by 4.

To Find :-

• Two consecutive odd Integer = ?

Answer :-

Let the two consecutive odd Integer be x and x + 2 respectively.

Where, x be the smaller odd Integer and x + 2 be larger odd Integer.

According to Question :-

→ 2x/5 = 2/9 (x + 2) + 4

→ 2x × 9 = 5 × 2(x + 2) + 4

→ 18x = 10(x + 2) + 4 × 45

→ 18x = 10x + 20 + 4 × 45

→ 18x - 10x = 20 + 180

→ 8x = 200

→ x = 200 ÷ 8

→ x = 25

Therefore,the two consecutive odd Integer is 25 and x + 2 = 25 + 2 = 27.