Question

Find two consecutive odd numbers such
that 6 times the smaller plus 3 times the
larger comes to 105.​

Answer 1

Answer:

Unless you mean two odd consecutive numbers, there are none. Alternatively, if the question was stated as 6 times the larger plus 3 times the smaller then that would work, but it is plain that the question does not state that. Thus as the question is stated, it has no valid solution.

Let the two numbers be x, and x+1

6x+3(x+1)=105

6x+3x+3=105

9x+3 -3 =105 -3

9x=102.

There is no solution that satisfies this question since 102 is not divisible by 9.

If you were asking for two odd consecutive numbers instead, then the two would be x, and x+2. In that situation:

6x+3(x+2)=105

6x+3x+6=105

9x+6 -6 =105 -6

9x=99

x=11, x+2=13

Thus if two consecutive odd numbers requested in the question, then 11, and 13 would satisfy that. Alternatively, if the question instead stated 6 times the larger plus 3 times the smaller, then:

6(x+1)+3x=105

6x+6+3x=105

9x+6 -6 =105 -6

9x=99

x=11, x+1=12

These are indeed consecutive numbers, but in the form that the question is presented, there is no valid solution.

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

1. 6x+3[x+1] =105