Question

Find two consecutive odd numbers such that six times the smaller plus four times the greater comes to 138
(Let the numbers be x and x+1)

Answer 1

Step-by-step explanation:

two consecutive odd numbers such that 6 times the smaller added to 4 times the greater comes to 138 .

Let the two numbers be n1 and n2,

where both n1 and n2 are odd

and n2 = n1 + 2. (since they are consectutive numbers)

We are told that,

6*n1 + 4*n2 = 138

3n1 + 2n2 = 69

3n1 + 2(n1 + 2) = 69

3n1 + 2n1 + 4 = 69

5n1 = 65

n1 = 13

n2 = 15

Answer 2

Answer:

x = 13

Step-by-step explanation:

let n1, n2 be two consecutive odd number

so let n1 = x and n2 = x+2

According to question, we have

6x + 4(x+2) = 138

6x + 4x + 8 = 138

6x + 4x = 138 - 8

10x = 130

x = 130/10

x = 13

Therefore,

n1 = 13

n2 = 15