Question

Find two consecutive odd numbers such that the sum of the greater number and 5 times the smaller number is 92

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\:\:$

$\green{\underline \bold{Given :}}$

$\:\:$

• Two consecutive odd numbers

• Sum of the greater number and 5 times the smaller number is 92

$\:\:$

$\red{\underline \bold{To \: Find:}}$

$\:\:$

• The consecutive odd numbers

$\:\:$

$\large{\orange{\underline{\tt{Solution :-}}}}$

$\:\:$

Let the first number be 'x'

Hence the other number which is consecutive to it is 'x + 2'

$\:\:$

$\purple{\underline \bold{According \: to \: the \ question :}}$

$\:\:$

Clearly 'x + 2' will be the greater number

$\:\:$

$\purple\longrightarrow$ $\sf x + 2 + 5x = 92$

$\:\:$

$\sf \longmapsto 6x + 2 = 92$

$\:\:$

$\sf \longmapsto 6x = 90$

$\:\:$

$\sf \longmapsto x = \dfrac { 90 } { 6 }$

$\:\:$

$\bf \dashrightarrow x = 15$

$\:\:$

$\underline{\bold{\texttt{Hence other number will be }}}$

$\:\:$

$\purple\longrightarrow$ 15 + 2

$\:\:$

$\bf \implies 17$

$\:\:$

Hence consecutive odd numbers will be 15 and 17

$\rule{200}5$

Answer 2

$\rule{200}3$

$\color{red}\huge{\underline{\underline{\mathfrak{Question:-}}}}$

Find two consecutive odd numbers such that the sum of the greater number and 5 times the smaller number is 92.

$\rule{200}3$

$\color{blue}\huge{\underline{\underline{\mathfrak{Answer}}}}$

${\bold{\pink{\text{Smaller number is 15}}}}$

${\bold{\pink{\text{Larger number is 17}}}}$

$\rule{200}3$

$\color{orange}\huge{\underline{\underline{\mathfrak{Solution:-}}}}$

${\bold{blue{\text{Given:-}}}}$

• Two consecutive odd numbers.
• Sum of greater number and 5 times smaller number is 92.

${\bold{\blue{\text{Let the smaller number be X}}}}$

${\bold{\blue{\text{Then tha larger number will be X+2}}}}$

${\bold{\orange{\text{Because they are odd consecutive number}}}}$

${\bold{\blue{\text{Now}}}}$

${\bold{\blue{\text{According to question}}}}$

${\blue{\left(x+2\right)+5\left(x\right) }}$${\blue{\implies}}$${\blue{\bold{92}}}$

${\bold{\blue{\text{x+2+5x}}}}$${\blue{\implies}}$${\blue{\bold{92}}}$

${\bold{\blue{\text{6x+2}}}}$${\blue{\implies}}$${\bold{\blue{92}}}$

${\bold{\blue{\text{6x = 92-2}}}}$

${\bold{\blue{\text{6x = 90}}}}$

${\bold{\blue{\text{x =}}}}$$\frac{90}{6}$

${\bold{\blue{\text{x = 15}}}}$

${\bold{\green{\text{Smaller number is 15}}}}$

${\bold{\green{\text{Larger number is 15+2=17}}}}$

$\rule{200}3$

Hope it helps