Question

find two consecutive odd numbers such that two- fifth of a smaller exceed two- ninth of the larger by 4​

Answer 1

Let the two numbers be x and x+2


Given, 2x/5 = 2/9( x+2) + 4

2x/5 = 2x/9 + 4/9 + 4

2x/5 - 2x/9 = 40/9

(18x - 10x)/45 = 40/9

8x = 200

x = 200/8

= 25.

The number will be 25 + 2 = 27.

Answer 2

Answer:

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Step-by-step explanation:

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