find two consecutive odd numbers such that two- fifth of a smaller exceed two- ninth of the larger by 4
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Let the two numbers be x and x+2
Given, 2x/5 = 2/9( x+2) + 4
2x/5 = 2x/9 + 4/9 + 4
2x/5 - 2x/9 = 40/9
(18x - 10x)/45 = 40/9
8x = 200
x = 200/8
= 25.
The number will be 25 + 2 = 27.
Given, 2x/5 = 2/9( x+2) + 4
2x/5 = 2x/9 + 4/9 + 4
2x/5 - 2x/9 = 40/9
(18x - 10x)/45 = 40/9
8x = 200
x = 200/8
= 25.
The number will be 25 + 2 = 27.
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