Question

find two consecutive odd numbers such that two fifth of the small number exceed two ninths of the larger​

Answer 1

Answer:

Therefore the two consecutive positive odd no. s are 25 and 27. Find two consecutive odd integers such that two-fifths of the smaller exceeds two-ninth of the greater by 4.

Answer 2

think u wanted to ask two consecutive odd integers not two consecutive Integers.because when I solved for two consecutive integers I assumed that the two numbers are x and x+1 but there exist no such numbers so I solved it for two consecutive odd integers.

let two consecutive nos be x and x+2

According to the question-

2x/5 = 2/9( x+2) + 4

2x/5 = 2x/9 + 4/9 + 4

2x/5 - 2x/9 = 40/9

(18x - 10x)/45 = 40/9

8x = 200

x = 200/8 = 25

Therefore the two consecutive positive odd no.s are 25 and 27.