Question

find two consecutive odd numbers such that two fifths of the smaller number exceeds two ninths of the larger by 4.

Answer 1

Answer:

Let the first consecutive number is 2x+1. Let the second consecutive number is 2x+3. So, product of two consecutive odd numbers = 2303. Hence, the greater number is 49.

Answer 2

Answer:

Given :-

➪ Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.

➪ ⅖ th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.

So, according to the question.

➪ 2x = 2 × (x + 2) + 4

5 9

➪ 2x = (2x + 4) + 4

5 9

Taking L.C.M. of the denominators of the right side, we get.

➪ 2x = (2x + 4 + 36)

5 9

Now, cross multiplying, we get.

➪ (2x*9) = 5*(2x + 40)

➪ 18x = 10x + 200

➪ 18x - 10x = 200

➪ 8x = 200

➪ x = 200

8

➪ x = 25

Putting the value of x, we get

➪ x + 2

➪ 25 + 2 = 27

So, the smaller integer is 25 and the greater odd integer is 27