Question

find two consecutive odd numbers such that two fifths of the smaller number exceeds two ninths of the larger by 4.

Answer 1

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Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4⇒ 2x/5 = (2x + 4)/9 + 4

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4⇒ 2x/5 = (2x + 4)/9 + 4Taking L.C.M. of the denominators of the right side, we get.

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4⇒ 2x/5 = (2x + 4)/9 + 4Taking L.C.M. of the denominators of the right side, we get.2x/5 = (2x + 4 + 36)/9

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4⇒ 2x/5 = (2x + 4)/9 + 4Taking L.C.M. of the denominators of the right side, we get.2x/5 = (2x + 4 + 36)/9Now, cross multiplying, we get.

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4⇒ 2x/5 = (2x + 4)/9 + 4Taking L.C.M. of the denominators of the right side, we get.2x/5 = (2x + 4 + 36)/9Now, cross multiplying, we get.⇒ (2x*9) = 5*(2x + 40)

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4⇒ 2x/5 = (2x + 4)/9 + 4Taking L.C.M. of the denominators of the right side, we get.2x/5 = (2x + 4 + 36)/9Now, cross multiplying, we get.⇒ (2x*9) = 5*(2x + 40)⇒ 18x = 10x + 200

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4⇒ 2x/5 = (2x + 4)/9 + 4Taking L.C.M. of the denominators of the right side, we get.2x/5 = (2x + 4 + 36)/9Now, cross multiplying, we get.⇒ (2x*9) = 5*(2x + 40)⇒ 18x = 10x + 200⇒ 18x - 10x = 200

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4⇒ 2x/5 = (2x + 4)/9 + 4Taking L.C.M. of the denominators of the right side, we get.2x/5 = (2x + 4 + 36)/9Now, cross multiplying, we get.⇒ (2x*9) = 5*(2x + 40)⇒ 18x = 10x + 200⇒ 18x - 10x = 200⇒ 8x = 200

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4⇒ 2x/5 = (2x + 4)/9 + 4Taking L.C.M. of the denominators of the right side, we get.2x/5 = (2x + 4 + 36)/9Now, cross multiplying, we get.⇒ (2x*9) = 5*(2x + 40)⇒ 18x = 10x + 200⇒ 18x - 10x = 200⇒ 8x = 200⇒ x = 200/8

Let x be the smaller odd integer and (x + 2) be the greater odd integer respectively.2/5th of the smaller odd integer exceeds 2/9th of the greater odd integer by 4.So, according to the question.2x/5 = 2/9*(x + 2) + 4⇒ 2x/5 = (2x + 4)/9 + 4Taking L.C.M. of the denominators of the right side, we get.2x/5 = (2x + 4 + 36)/9Now, cross multiplying, we get.⇒ (2x*9) = 5*(2x + 40)⇒ 18x = 10x + 200⇒ 18x - 10x = 200⇒ 8x = 200⇒ x = 200/8 ⇒ x = 25

Answer 2

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