find two consecutive odd numbers whose sum is 136
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Since odd integers are also 2 units apart, the second consecutive odd integer will be 2 more than the first. Therefore, ( 2 k + 1 ) + ( 2 ) = 2 k + 3 \left( {2k + 1} \right) + \left( 2 \right) = 2k + 3 (2k+1)+(2)=2k+3 where 2 k + 3 2k + 3 2k+3 is the second
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