Find two consecutive odd positive ineger sum of whose square is 290
Answers
Answered by
0
The finding process :
= 290÷2
= 145
So the integers are 145 and next number 146...
= 290÷2
= 145
So the integers are 145 and next number 146...
Answered by
0
NOT SURE ABOUT CONSECUTIVE ODD POSITIVE INTEGER
but can answer about odd positive odd numbers
i can give u two sets
1) [17, 1] 17^2 = 289 and 1^2 = 1
if u add its squares u will get 290
2) [13, 11] 13^2 = 169 and 11^2 = 121
hope so it will useful to my all frndz........
but can answer about odd positive odd numbers
i can give u two sets
1) [17, 1] 17^2 = 289 and 1^2 = 1
if u add its squares u will get 290
2) [13, 11] 13^2 = 169 and 11^2 = 121
hope so it will useful to my all frndz........
Similar questions