Question

Find two consecutive odd positive intege.rs , sum of whose square is 290

Answer 1

Answer:

let first odd positive integer bex

let the next integer bex+2

acc to question

x2+(x+2)2=290

x2+x2+4+4x=290

2x2+4x−286=0

x2+2x−143=0

x2+13x−11x−143=0

x(x+13)−11(x+13)=0

(x−11)(x+13)=0

x=11,−13

as x cant be negative, so x=11

x+2=13

answer