Find two consecutive odd positive integer , sum of whose square is 290
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Answer:
The two consecutive odd positive integers, sum of whose square is 290 are 11 and 13. So, the correct answer is “11 and 13”.
Step-by-step explanation:
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Step-by-step explanation:
Let one number be x and other be x+2
ATQ
(x+x+2)²=290
(2x+2)²=290
(2x)²+2(2x×2)+(2)²=290
4x²+8x+2=290
4x²+8x=288
4x(x+2)=288
x(x+2)=288/4
x(x+2)=72
x+2=72/x
2=72/x-2
2=72-2x/x
2x=72-2x
2x+2x=72
4x=72
x=72/4
x=18
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