find two consecutive odd positive integer sum of whose squares is 970.
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Answered by
20
let it be x and x+1
x2 + (x+1)2 = 970
x2 + x2 +1 +2x=970
2x2 + 2x +1 = 970
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solve the equation and you are done.
x2 + (x+1)2 = 970
x2 + x2 +1 +2x=970
2x2 + 2x +1 = 970
Â
solve the equation and you are done.
Answered by
34
this is your complete answer
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