Math, asked by TreeckoPlays, 7 months ago

Find two consecutive odd positive integers such that two-fifth of the smaller exceeds two-ninth of the greater by 4.

Answers

Answered by Anonymous
1

Answer:

Thus the numbers are 25 and 27

Step-by-step explanation:

Let the consecutive odd numbers are x and x+2

2/5(x) =(x+2)*2/9 +4

2*9x=5(x+2)*2 +4*9*5

18x=10x+20+180

8x=200

x=200/8=25

Thus the numbers are 25 and 27

Answered by Anonymous
8

Answer:

X = 25

numbers are 25 and 27

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