Question

Find two consecutive odd positive integers. Sum of whose square is 290​

Answer 1

Answer:

Step-by-step explanation:

Let,

1st odd positive number is x+1

2nd odd positive number is x+3

then,

(x+1)^2 + (x+3)^2 = 290

(x^2 + 1 + 2x) + (x^2 + 9 + 6x) = 290

2x^2 8x + 10 = 290

2x^2 + 8x = 280

x^2  4x = 140

x^2 + 4x - 140 = 0

x^2 + 14x - 10x - 140 =0

x(x + 14) - 10(x + 14) =0

(x - 10) (x + 14) = 0

Now

we get two value of x.

x = 10

x = - 14

Here we only consider positive number according to question,

x = 10

Hence, 1st odd positive number is 11 and 2nd odd positive number is 13.

Answer 2

Step-by-step explanation:

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