Question

find two consecutive odd positive integers sum of whose squares is 290​

Answer 1

Answer:

I don't know about it

Step-by-step explanation:

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Answer 2

Answer:

Let the two consecutive odd numbers are a and a + 2

Given, sum of square of two consecutive odd numbers is 290

=> a2 + (a + 2)2 = 290

=> a2 + a2 + 4a + 4 = 290

=> 2a2 + 4a + 4 = 290

=> 2a2 + 4a + 4 - 290 = 0

=> 2a2 + 4a - 286 = 0

=> 2(a2 + 2a - 143) = 0

=> a2 + 2a - 143 = 0

=> a2 + 13a - 11a - 143 = 0

=> a(a + 13) - 11(a + 13) = 0

=> (a + 13)*(a - 11) = 0

=> a = 11, -13

Since number is positive,

So, a = 11

Now, a + 2 = 11 + 2 = 13

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