Question

find two consecutive odd positive integers , sum of whose square is 290​

Answer 1

Answer:

2x+1 and 2x+3

Step-by-step explanation:

(2x+1)^ +(2x+3)^=290

4x^+1+4x+4x^+9+12x=290

8x^+16x+10=290

8x^+16x-280

x^+2x-35

x^+(7-5)x-35

x^+7x-5x-35

x(x+7)-5(x+7)

(x+7)(x-5)

x=-7(does not exist)

x=5

so x= 5

so two nos.are 11 and 13

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