Question

Find two consecutive odd positive integers, sum of whose square is 290.
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Answer 1

Answer:

The two consecutive positive odd integers are 11 and 13

Step-by-step explanation:

Let the two consecutive positive odd integers be x and x+2

x²+(x+2)²=290

x²+x²+4+2*x*2=290

2x²+4x+4=290

2x²+4x+4-290=0

2x²+4x-286=0

By splitting middle term method, we get

2x²+26x-22x-286=0

2x(x+13)-22(x+13)=0

(2x-22)(x+13)=0

2x-22=0, x+13=0

2x=22, x=-13

x=11, x= -13

But since x is positive, x is 11 and not -13

x+2 =11+2= 13

Therefore the two consecutive positive odd integers are 11 and 13

Answer 2

Answer:

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Step-by-step explanation:

Solution is given in above pic

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