Question

find two consecutive odd positive integers, sum of whose square is 290​

Answer 1

Explanation:

let the consecutive odd positive integers be

x, x +1 ( x is even and x+1 ia odd)

A/q -- x² + ( x + 1 )² = 290

x² + x² +1 + 2 x = 290

2 x² + 2 x = 290 -1

2 x² +2 x = 289

2 x² +2 x -289 = 0