Question

find two consecutive odd positive integers,sum of whose squares is 290​

Answer 1

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Answer 2

Answer:

let first no.be x and 2nd no. be (x+2)

so, x^2 +(x+2)^2=290

x^2+x^2+4+4x=290

2x^2+4x=286

x^2+2x=143

x^2+2x -143=0

x^2+13x-11x -143=0

x(x+13) -11 (x+13)=0

so, x+13=0. or x-11=0. ,x=11

x= -13 (but we want only positive integer )

so, x=11

and 2nd number =13

verification=11^2+13^2=290

121+169=290