Question

find two consecutive odd positive integers,sum of whose squares is 394

Answer 1

Answer:

So, Two no. are -15 and 13

Step-by-step explanation:

Let the two consecutive odd numbers be x and x+2.

x²+ (x²+2)2= 394

x²+ x²+ 4x + 2²= 394

2x²+ 4x + 4 = 394 .......( dividing the equation by 2)

x²+2x =(394 - 4)/2

x²+ 2x = 195

x²+2x - 195 = 0

x²+ 15x - 13x -195 = 0 .............( by factorization method )

x( x + 15 ) - 13( x + 15 ) = 0

( x + 15 ) ( x - 13 )

x = -15 OR x = 13

Answer 2

The sum of the squares of two consecutive odd NUMBERS is 394.find the numbers Get the answers ... We are taking the value of x to be 13 as it is a positive number.

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