Question

Find two consecutive odd positive integers sun of whose squares is 290

Answer 1

Answer:

first odd integer = x

second odd integer = x + 2

then

x^2 + (x+2)^2 = 290

x^2 + x^2 + 4 + 4x = 290

2x^2 + 4x - 286 = 0

put x = 11

2 × (11)^2 + 4 × 11 - 286 = 0

2 × (121) + 44 - 286 = 0

242 + 44 - 286 = 0

286 - 286 = 0

0 = 0

lhs = Rhs

Answer 2

$\huge \sf \red{ᴀɳรωεɾ}$

เ ɦσρε µρρεɾ αƭƭαcɦɱεɳƭ ωเℓℓ ɦεℓρ ყσµ✌