Question

Find two consecutive odd positive integers the squares are 240

Answer 1

Let first number be x

And second number be( x+1)

ATQ

X(X +1) = 240

X^2 + X = 240

X^2 + X -240 =0

X ^2 +16X - 15X - 240 =0

X (X+16)-15(X+16) =0

(X-15)(X+16) =0

X = 15 where X = -16 rejecting