find two consecutive odd positive integers whose product is 35
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Answered by
2
Answer:
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Step-by-step explanation:
x = one odd integer
x+2 = next consecutive odd integer
x(x+2)=35
x2 +2x =35
-35=-35
x2 +2x - 35 = 0
(x+7)(x-5)=0
x+7 = 0 x-5 =0
x=-7 x=5
-7 +2 = -5
the two negative solutions are x=-7 and x+2=-5
5+2 = 7
the two positive solutions are x = 5 and x+2 = 7
Answered by
1
Answer:
x(x+2)= 35
x^2 + 2x - 35 = 0
(x - 5)(x - 7) = 0
x = 5, 7
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