Question

find two consecutive positive even integers whose product is 288.​

Answer 1

Answer:

Let the first integer = x

this means that the next integer must be x+2(it's even)

 

So we know x(x+2) = 288

x^2 + 2x = 288

x^2 + 2x - 288 = 0

(x - 16)(x+18) = 0

x = 16 or -18

x + 2 would be 18 or -16

so 16, 18 is your answer or -18, -16

Step-by-step explanation: