Question

find two consecutive positive even numbers if difference of their square is 20​

Answer 1

Answer:

4 and 6

Step-by-step explanation:

Let the two consecutive positive even numbers be 2n and 2n+2

As per the question,

(2n+2)^2 - (2n)^2 = 20

(4n^2 + 8n + 4) - 4n^2 = 20

4n^2 - 4n^2 + 8n + 4 = 20

8n = 16

n = 2

Therefore,

First number = 2n = 2 × 2 = 4

Second number = 2n + 2 = 2 × 2 + 2 = 6.

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