Question

find two consecutive positive integer sum of whose suquare is 365

Answer 1

Answer:

Let the numbers be x,x+1

Given that x^2+(x+1)^2=365

x^2+x^2+2x +1=365

2x^2+2x +1=365

2x^2+2x -364=0

x^2+x -182=0

x^2+14x-13x-182=0

x(x+14)-13(x+14)=0

That is x=13,-14

Answer 2

the two consecutive positive integer whose square sum is 365 is 13 and .14

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