Math, asked by charchit54, 1 year ago

find two consecutive positive integers sum of whose square is 365 ​

Answers

Answered by antareepray2
25

Let the numbers be x and (x+1), then;

x + (x+1) = 365

or, 2x = 364

or, x = 182

Hence, the numbers are 182 and 183.

HOPE THIS COULD HELP!!!

Answered by Blaezii
15

Answer:

Required numbers are 13 and 14

Step-by-step explanation:

Let two consecutive positive integer be x and x+1

According to your question:

x^2+(x+1)^2 = 365

>>>>x^2+x^2+2x+1 =365

>>>>>2x^2+2x-364 = 0

>>>>>x^2+x - 182 = 0

Let us spilt the middle term,

>>>>x^2+14x-13x-182 =0

>>>>x(x+14) - 13 (x+14) = 0

>>>>> (x+14)(x - 13) = 0

x = - 14 or x = 13

[ - ve root being rejected ]

Hence, required numbers are 13 and 14

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