find two consecutive positive integers, sum of whose square is 365.
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Answered by
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Answer:
consecutive numbers are 13 and 14 (。_。)
Step-by-step explanation:
let the two consecutive positive integers are x and y
y - 1 = x => y = x + 1
x^2 + y^2 = 365
x^2 + (x+1)^2 = 365
2x^2 + 2x + 1 = 365
x^2 + x - 182 = 0
x^2 + 14x - 13x -182 = 0
x(x + 14) -13 (x+14) = 0
x = +13 (not accepted) OR x = -14
Thus the two consecutive numbers are 13 and 14.
I hope u find it useful. ╮(╯▽╰)╭
Answered by
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Answer:
Step-by-step explanation:
It is the correct answer.
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