Question

find two consecutive positive integers sum of whose square is 365 ​

Answer 1

Step-by-step explanation:

11 and 12 are the two consecutive positive integers by the sum of square is 365

Answer 2

Answer:

let first integer be x

then, second integer = x + 1

according to question ,

x² + ( x + 1)² = 365

x² + x² + 1 + 2x = 365

2x² + 2x +1 - 365 = 0

2x² + 2x - 364 = 0

x ² + x - 182 = 0

x² + 14x - 13x - 182 = 0

x ( x + 14 ) - 13 ( x + 14) = 0

( x - 13) (x + 14) = 0

x = 13 or x = - 14

taking positive value of x

then

first integer = 13

and second integer = 13 + 1 = 14